1836 United States presidential election in Pennsylvania
The 1836 United States presidential election in Pennsylvania took place between November 3 and December 7, 1836, as part of the 1836 United States presidential election. Voters chose 30 representatives, or electors to the Electoral College, who voted for President and Vice President.
![]() | ||||||||||||||||||||||||||
| ||||||||||||||||||||||||||
| ||||||||||||||||||||||||||
|
Elections in Pennsylvania | ||||||||||||||
---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|
![]() | ||||||||||||||
|
||||||||||||||
|
||||||||||||||
|
||||||||||||||
|
||||||||||||||
Pennsylvania voted for the Democratic candidate, Martin Van Buren, over the Whig candidate, William Henry Harrison. Van Buren won Pennsylvania by a margin of 2.36%.
Results
1836 United States presidential election in Pennsylvania[1] | |||||
---|---|---|---|---|---|
Party | Candidate | Votes | Percentage | Electoral votes | |
Democratic | Martin Van Buren | 91,457 | 51.18% | 30 | |
Whig | William Henry Harrison | 87,235 | 48.82% | 0 | |
Totals | 178,692 | 100.0% | 30 | ||
gollark: Ah, cool.
gollark: What's that? An anomalous array programming operation presumably, but what does it do?
gollark: A "real" Macron, if this isn't that.
gollark: Yes.
gollark: Again, without a counterexample your statement is ridiculous.
References
- "1836 Presidential General Election Results - Pennsylvania". U.S. Election Atlas. Retrieved 4 August 2012.
This article is issued from Wikipedia. The text is licensed under Creative Commons - Attribution - Sharealike. Additional terms may apply for the media files.