1826 Pennsylvania gubernatorial election

The Pennsylvania gubernatorial election of 1826 occurred on October 10, 1826. Incumbent Democratic governor, John Andrew Shulze, defeated Federalist candidate John Sergeant by a wide margin.

Pennsylvania gubernatorial election, 1826
October 10, 1826 (1826-10-10)
 
Nominee John Andrew Shulze
Party Democratic
Popular vote 72,710
Percentage 96.9%
County Results
Shulze:      60-70%      70-80%      80-90%      90-100%
Sergeant:      50-60%
Governor before election

John Andrew Shulze
Democratic

 Elected Governor

John Andrew Shulze
Democratic

Elections in Pennsylvania

Results
Pennsylvania gubernatorial election, 1826[1]
Party Candidate Votes %
Democratic John Andrew Shulze (incumbent) 72,710 96.87
Federalist John Sergeant 1,175 1.57
N/A Others 1,174 1.56
Total votes 75,059 100.00
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gollark: Piscine entities, I believe.
gollark: I guess this is you then.

References
  1. "PA Governor General Election". OurCampaigns. Retrieved 3 July 2012.


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