1836 United States presidential election in Connecticut

The 1836 United States presidential election in Connecticut took place between November 3 and December 7, 1836, as part of the 1836 United States presidential election. Voters chose 8 representatives, or electors to the Electoral College, who voted for President and Vice President.

Main article: 1836 United States presidential election

1836 United States presidential election in Connecticut

November 3 – December 7, 1836

Nominee Martin Van Buren William Henry Harrison Party Democratic Whig Home state New York Ohio Running mate Richard Johnson Francis Granger Electoral vote 8 0 Popular vote 19,294 18,799 Percentage 50.65% 49.35%

Connecticut voted for the Democratic candidate, Martin Van Buren, over Whig candidate William Henry Harrison. Van Buren won Connecticut by a narrow margin of 1.3%.

As a result of his win, Van Buren also became the first Democratic presidential candidate to carry Connecticut.

Results

1836 United States presidential election in Connecticut[1]
Party		Candidate	Votes	Percentage	Electoral votes
	Democratic	Martin Van Buren	19,294	50.65%	8
	Whig	William Henry Harrison	18,799	49.35%	0
Totals			38,093	100.0%	8

References

1. "1836 Presidential General Election Results - Connecticut". U.S. Election Atlas. Retrieved 4 August 2012.