1836 United States presidential election in Missouri
The 1836 United States presidential election in Missouri took place between November 3 and December 7, 1836, as part of the 1836 United States presidential election. Voters chose four representatives, or electors to the Electoral College, who voted for President and Vice President.
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Elections in Missouri | ||||||||||||||||
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Missouri voted for the Democratic candidate, Martin Van Buren, over Whig candidate Hugh White. Van Buren won Missouri by a margin of 19.96%.
Results
United States presidential election in Missouri, 1836[1] | |||||
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Party | Candidate | Votes | Percentage | Electoral votes | |
Democratic | Martin Van Buren | 10,995 | 59.98% | 4 | |
Whig | Hugh White | 7,337 | 40.02% | 0 | |
Totals | 18,332 | 100.0% | 4 | ||
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References
- "1836 Presidential General Election Results - Missouri". U.S. Election Atlas. Retrieved 15 April 2013.
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