Cormenon

Cormenon is a commune in the Loir-et-Cher department of central France.

Cormenon
Coat of arms
Location of Cormenon
Cormenon
Cormenon
Coordinates: 47°58′09″N 0°53′40″E
CountryFrance
RegionCentre-Val de Loire
DepartmentLoir-et-Cher
ArrondissementVendôme
CantonLe Perche
IntercommunalityCollines du Perche
Government
  Mayor (20142020) Gilles Boulay
Area
1
5.76 km2 (2.22 sq mi)
Population
 (2017-01-01)[1]
690
  Density120/km2 (310/sq mi)
Time zoneUTC+01:00 (CET)
  Summer (DST)UTC+02:00 (CEST)
INSEE/Postal code
41060 /41170
Elevation102–210 m (335–689 ft)
(avg. 110 m or 360 ft)
1 French Land Register data, which excludes lakes, ponds, glaciers > 1 km2 (0.386 sq mi or 247 acres) and river estuaries.

Population

Historical population
YearPop.±%
1793350    
1806432+23.4%
1821479+10.9%
1831465−2.9%
1841464−0.2%
1851474+2.2%
1861446−5.9%
1872480+7.6%
1881696+45.0%
1891606−12.9%
1901772+27.4%
1911667−13.6%
1921607−9.0%
1931655+7.9%
1946602−8.1%
1954520−13.6%
1962557+7.1%
1968655+17.6%
1975756+15.4%
1982733−3.0%
1990717−2.2%
1999690−3.8%
2008690+0.0%
2013698+1.2%
gollark: I'm not entirely sure how, but it seems to construct a tree/maybe deterministic finite automaton/finite state machine/I don't know theoretical CS which matches anagrams and unmatches unanagrams.
gollark: ```pythonimport collectionsdef do_thing(s): if len(s) == 1: return { s[0]: True } out = {} for i, c in enumerate(s): without = s[:i] + s[i + 1:] things = do_thing(without) out[c] = things return outdef match(r, s): print(r) c = r for i, x in enumerate(s): print(x) try: c = c[x] if c == True: if i + 1 == len(s): return True # full match else: return False # characters remain except KeyError: return False # no match return False # incomplete matchentry = lambda a, b: match(do_thing(a.lower().replace(" ", "")), b.lower().replace(" ", ""))```Here is my entry (pending a port to osmarkslisp™️). This is definitely my entry.
gollark: I wish to use Mathematica in my code. Please install it. DO NOT READ, ubq.
gollark: I have a "great" way to do this which I think takes O(n²) space-time-beeite.
gollark: Perhaps it is also possible to construct some sort of regex/deterministic finite automaton to match things matching anagramatically.

See also

References

  1. "Populations légales 2017". INSEE. Retrieved 6 January 2020.



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