1896 United States presidential election in South Dakota

The 1896 United States presidential election in South Dakota took place on November 3, 1896. All contemporary 45 states were part of the 1896 United States presidential election. Voters chose four electors to the Electoral College, which selected the president and vice president.

Main article: 1896 United States presidential election

1896 United States presidential election in South Dakota

November 3, 1896

Nominee William J. Bryan William McKinley Party Democratic Republican Home state Nebraska Ohio Running mate Arthur Sewall Garret Hobart Electoral vote 4 0 Popular vote 41,225 41,042 Percentage 49.70% 49.48%

President before election Grover Cleveland Democratic Elected President William McKinley Republican

South Dakota was won by the Democratic nominees, former U.S. Representative William Jennings Bryan of Nebraska and his running mate Arthur Sewall of Maine. Two electors cast their Vice Presidential ballots for Thomas E. Watson.

Bryan won the state by a very narrow margin of 0.22 percentage points, becoming the first Democratic presidential candidate to win the state. Bryan would later lose the state to Republican incumbent president William McKinley four years later and would later lose the state again to William Howard Taft in 1908.

Results

1896 United States presidential election in South Dakota[1]
Party		Candidate	Votes	Percentage	Electoral votes
	Democratic	William Jennings Bryan	41,225	49.70%	4
	Republican	William McKinley	41,042	49.48%	0
	Prohibition	Joshua Levering	683	0.82%	0
Totals			82,950	100.00%	4
Voter turnout					—

References

1. Dave Leip's U.S. Election Atlas; Presidential General Election Results – South Dakota

Notes