1896 United States presidential election in Minnesota

The 1896 United States presidential election in Minnesota took place on November 3, 1896. All contemporary 45 states were part of the 1896 United States presidential election. Minnesota voters chose nine electors to the Electoral College, which selected the president and vice president.

Main article: 1896 United States presidential election

1896 United States presidential election in Minnesota

November 3, 1896

Nominee William McKinley William J. Bryan Party Republican Democratic Home state Ohio Nebraska Running mate Garret Hobart Arthur Sewall Electoral vote 9 0 Popular vote 193,503 139,735 Percentage 53.77% 40.89%

County Results

President before election Grover Cleveland Democratic Elected President William McKinley Republican

Minnesota was won by the Republican nominees, former Ohio Governor William McKinley and his running mate Garret Hobart of New Jersey.

Results

1896 United States presidential election in Minnesota[1]
Party		Candidate	Votes	Percentage	Electoral votes
	Republican	William McKinley	193,503	53.77%	9
	Democratic	William Jennings Bryan	139,735	40.89%	0
	Prohibition	Joshua Levering	4,348	1.27%	0
	National Democratic	John M. Palmer	3,222	0.94%	0
	Socialist Labor	Charles Matchett	954	0.28%	0
Totals			341,762	100.00%	9
Voter turnout					—

References

1. Dave Leip's U.S. Election Atlas; Presidential General Election Results – Minnesota

Notes