1920 United States presidential election in Missouri
The 1920 United States presidential election in Missouri took place on November 2, 1920, as a part of the United States Presidential election. Voters chose 14 representatives, or electors, to the Electoral College, who voted for president and vice president.
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The Republican candidate, Warren Harding, won the state of Missouri and collected its 18 electoral votes.[1]
Results
| Party | Candidate | Votes | % | |
|---|---|---|---|---|
| Republican | Warren G. Harding | 727,162 | 54.56% | |
| Democratic | James M. Cox | 574,799 | 43.13% | |
| Socialist | Eugene Debs | 20,242 | 1.52% | |
| Prohibition | Aaron S. Watkins | 5,142 | 0.39% | |
| Farmer–Labor | Parley Christiansen | 3,291 | 0.25% | |
| Socialist Labor | William Cox | 2,164 | 0.16% | |
| Total votes | 1,332,800 | 100% | ||
gollark: Antimatter? *Really*?
gollark: Obviously not.
gollark: We don't use nuclear fission unironically.
gollark: Yes, mass-energy conversion good.
gollark: Idea: instead of "nuclear reactors", directly convert mass into energy.
References
- "Dave Leip's Atlas of U.S. presidential elections". Dave Leip's Atlas of U.S. Presidential Elections.
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State and district results of the 1920 United States presidential election | ||
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