1816 United States presidential election in Ohio

The 1820 United States presidential election in Ohio took place between November 1 and December 4, 1816, as part of the 1816 United States presidential election. Voters chose 8 representatives, or electors to the Electoral College, who voted for President and Vice President.

Main article: 1816 United States presidential election
1816 United States presidential election in Ohio
November 1 – December 4, 1816
 
Nominee James Monroe Rufus King
Party Democratic-Republican Federalist
Home state Virginia New York
Running mate Daniel D. Tompkins John E. Howard
Electoral vote 8 0
Popular vote 3,326 593
Percentage 84.87% 15.13%
President before election

James Madison
Democratic-Republican

 Elected President

James Monroe
Democratic-Republican

Elections in Ohio

Ohio elected Democratic-Republican candidate James Monroe over Federalist candidate Rufus King. Monroe won Ohio by a margin of 69.74%.

Results
1816 United States presidential election in Ohio[1]
Party Candidate Votes Percentage Electoral votes
Democratic-Republican James Monroe 3,326 84.87% 8
Federalist Rufus King 593 15.13% 0
Totals 3,919 100.0% 8
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References
  1. Ohio. Secretary of State. (1909). Ohio election statistics: the general election. Springfield, Ohio: The Springfield Publishing Company, State Printers. p. 3. OCLC 5470967. Retrieved 2019-12-08.


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