1824 United States presidential election in Ohio

1824 United States presidential election in Ohio
	October 26 – December 2, 1824
	October 26 – December 2, 1824
President before election; James Monroe; Democratic-Republican	Elected President ; John Quincy Adams; Democratic-Republican

The 1824 United States presidential election in Ohio took place between October 26 and December 2, 1824, as part of the 1824 United States presidential election. Voters chose 16 representatives, or electors to the Electoral College, who voted for President and Vice President.

During this election, the Democratic-Republican Party was the only major national party, and four different candidates from this party sought the Presidency. Ohio voted for Henry Clay over Andrew Jackson, John Quincy Adams, and William H. Crawford. Clay won Ohio by a margin of 1.53%.

Results

1824 United States presidential election in Ohio[1]
Party		Candidate	Votes	Percentage	Electoral votes
	Democratic-Republican	Henry Clay	19,255	38.49%	16
	Democratic-Republican	Andrew Jackson	18,489	36.96%	0
	Democratic-Republican	John Quincy Adams	12,280	24.55%	0
Totals			50,024	100.0%	16

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