1918 Rhode Island gubernatorial election

The 1918 Rhode Island gubernatorial election was held on November 5, 1918. Incumbent Republican Robert Livingston Beeckman defeated Democratic nominee Alberic A. Archambault with 53.11% of the vote.

1918 Rhode Island gubernatorial election
November 5, 1918
 
Nominee Robert Livingston Beeckman Alberic A. Archambault
Party Republican Democratic
Popular vote 42,682 36,031
Percentage 53.11% 44.84%
Governor before election

Robert Livingston Beeckman
Republican

 Elected Governor

Robert Livingston Beeckman
Republican

Elections in Rhode Island

General election

Candidates

Major party candidates

  • Robert Livingston Beeckman, Republican
  • Alberic A. Archambault, Democratic

Other candidates

  • Ernest Sherwood, Socialist

Results
1918 Rhode Island gubernatorial election[1]
Party Candidate Votes % ±
Republican Robert Livingston Beeckman 42,682 53.11%
Democratic Alberic A. Archambault 36,031 44.84%
Socialist Ernest Sherwood 1,648 2.05%
Majority 6,651
Turnout
Republican hold Swing

References
  1. "Congressional Quarterly's Guide to U.S. elections". Books.google.com. Retrieved May 20, 2020.
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