1899 Rhode Island gubernatorial election

The 1899 Rhode Island gubernatorial election was held on April 5, 1899. Incumbent Republican Elisha Dyer Jr. defeated Democratic nominee George W. Greene with 56.36% of the vote.

1899 Rhode Island gubernatorial election
April 5, 1899
 
Dem
SLP
Nominee Elisha Dyer Jr. George W. Greene Thomas F. Herrick
Party Republican Democratic Socialist Labor
Popular vote 24,308 14,602 2,941
Percentage 56.36% 33.86% 6.82%
Governor before election

Elisha Dyer Jr.
Republican

 Elected Governor

Elisha Dyer Jr.
Republican

Elections in Rhode Island

General election

Candidates

Major party candidates

  • Elisha Dyer Jr., Republican
  • George W. Greene, Democratic

Other candidates

  • Thomas F. Herrick, Socialist Labor
  • Joseph A. Peckham, Prohibition

Results
1899 Rhode Island gubernatorial election[1]
Party Candidate Votes % ±
Republican Elisha Dyer Jr. 24,308 56.36%
Democratic George W. Greene 14,602 33.86%
Socialist Labor Thomas F. Herrick 2,941 6.82%
Prohibition Joseph A. Peckham 1,279 2.97%
Majority 9,706
Turnout
Republican hold Swing
gollark: I just don't find it very practicalm
gollark: Rust + Haskell = Ruskskellt.
gollark: 20 cases? Madness.
gollark: It's very composable.
gollark: Alternately, `You XOR Your intelligence = You`.

References
  1. "Congressional Quarterly's Guide to U.S. elections". Books.google.com. Retrieved July 15, 2020.
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