1930 Rhode Island gubernatorial election

The 1930 Rhode Island gubernatorial election was held on November 4, 1930. Incumbent Republican Norman S. Case defeated Democratic nominee Theodore F. Green with 50.53% of the vote.

1930 Rhode Island gubernatorial election
November 4, 1930
 
Nominee Norman S. Case Theodore F. Green
Party Republican Democratic
Popular vote 112,070 108,558
Percentage 50.53% 48.95%
Governor before election

Norman S. Case
Republican

 Elected Governor

Norman S. Case
Republican

Elections in Rhode Island

General election

Candidates

Major party candidates

  • Norman S. Case, Republican
  • Theodore F. Green, Democratic

Other candidates

  • Charles H. Dana, Socialist

Results
1930 Rhode Island gubernatorial election[1]
Party Candidate Votes % ±
Republican Norman S. Case 112,070 50.53%
Democratic Theodore F. Green 108,558 48.95%
Socialist Charles H. Dana 1,168 0.53%
Majority 3,512
Turnout
Republican hold Swing
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gollark: https://killedbygoogle.com/
gollark: * spies on you all the time and randomly has things be cancelled
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gollark: That's a BAD thing.

References
  1. "Congressional Quarterly's Guide to U.S. elections". Books.google.com. Retrieved May 7, 2020.
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