1940 Rhode Island gubernatorial election
The 1940 Rhode Island gubernatorial election was held on November 5, 1940. Democratic nominee J. Howard McGrath defeated incumbent Republican William Henry Vanderbilt III with 55.84% of the vote.
![]() | |||||||||||||||||
| |||||||||||||||||
| |||||||||||||||||
|
General election
Candidates
Major party candidates
- J. Howard McGrath, Democratic
- William Henry Vanderbilt III, Republican
Other candidates
- Wilfred J. Boissy, Communist
Results
Party | Candidate | Votes | % | ± | |
---|---|---|---|---|---|
Democratic | J. Howard McGrath | 177,937 | 55.84% | ||
Republican | William Henry Vanderbilt III | 140,480 | 44.08% | ||
Communist | Wilfred J. Boissy | 257 | 0.08% | ||
Majority | 37,457 | ||||
Turnout | |||||
Democratic gain from Republican | Swing | ||||
gollark: Heck you UTTERLY.
gollark: * bzzzz
gollark: No, not really, it seems to have more independent agency in each "neuron".
gollark: So some sort of weird multi-agent system where you have to hope one of the bees randomly learns to run your program right?
gollark: Interesting idea!
References
- "Congressional Quarterly's Guide to U.S. elections". Books.google.com. Retrieved April 30, 2020.
This article is issued from Wikipedia. The text is licensed under Creative Commons - Attribution - Sharealike. Additional terms may apply for the media files.