1906 Rhode Island gubernatorial election

The 1906 Rhode Island gubernatorial election was held on November 6, 1906. Democratic nominee James H. Higgins defeated incumbent Republican George H. Utter with 49.92% of the vote.

1906 Rhode Island gubernatorial election
November 6, 1906
 
Nominee James H. Higgins George H. Utter
Party Democratic Republican
Popular vote 33,195 31,877
Percentage 49.92% 47.94%
Governor before election

George H. Utter
Republican

 Elected Governor

James H. Higgins
Democratic

Elections in Rhode Island

General election

Candidates

Major party candidates

  • James H. Higgins, Democratic
  • George H. Utter, Republican

Other candidates

  • Bernan E. Helme, Prohibition
  • Warren A. Carpenter, Socialist
  • David J. Moran, Socialist Labor

Results
1906 Rhode Island gubernatorial election[1]
Party Candidate Votes % ±
Democratic James H. Higgins 33,195 49.92%
Republican George H. Utter 31,877 47.94%
Prohibition Bernan E. Helme 714 1.07%
Socialist Warren A. Carpenter 395 0.59%
Socialist Labor David J. Moran 320 0.48%
Majority 1,318
Turnout
Democratic gain from Republican Swing
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References
  1. "Congressional Quarterly's Guide to U.S. elections". Books.google.com. Retrieved July 10, 2020.
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