1893 Rhode Island gubernatorial election

The 1893 Rhode Island gubernatorial election was held on April 5, 1893. Incumbent Republican Daniel Russell Brown defeated Democratic nominee David S. Baker with 46.34% of the vote.

1893 Rhode Island gubernatorial election
April 5, 1893
 
Dem
Nominee Daniel Russell Brown David S. Baker Henry B. Metcalf
Party Republican Democratic Prohibition
Popular vote 21,830 22,015 3,265
Percentage 46.34% 46.73% 6.93%
Governor before election

Daniel Russell Brown
Republican

 Elected Governor

Daniel Russell Brown
Republican

Elections in Rhode Island

General election

Candidates

Major party candidates

  • Daniel Russell Brown, Republican
  • David S. Baker, Democratic

Other candidates

  • Henry B. Metcalf, Prohibition

Results
1893 Rhode Island gubernatorial election[1]
Party Candidate Votes % ±
Republican Daniel Russell Brown 21,830 46.34%
Democratic David S. Baker 22,015 46.73%
Prohibition Henry B. Metcalf 3,265 6.93%
Majority 185
Turnout
Republican hold Swing
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References
  1. "Congressional Quarterly's Guide to U.S. elections". Books.google.com. Retrieved July 20, 2020.
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