1902 Rhode Island gubernatorial election

The 1902 Rhode Island gubernatorial election was held on November 4, 1902. Democratic nominee Lucius F. C. Garvin defeated incumbent Republican Charles D. Kimball with 53.99% of the vote.

1902 Rhode Island gubernatorial election

November 4, 1902
 
Nominee Lucius F. C. Garvin Charles D. Kimball
Party Democratic Republican
Popular vote 32,279 24,541
Percentage 53.99% 41.04%

Governor before election

Charles D. Kimball
Republican

Elected Governor

Lucius F. C. Garvin
Democratic

General election

Candidates

Major party candidates

  • Lucius F. C. Garvin, Democratic
  • Charles D. Kimball, Republican

Other candidates

  • William E. Brightman, Prohibition
  • Peter McDermott, Socialist Labor

Results

1902 Rhode Island gubernatorial election[1]
Party Candidate Votes % ±
Democratic Lucius F. C. Garvin 32,279 53.99%
Republican Charles D. Kimball 24,541 41.04%
Prohibition William E. Brightman 1,689 2.83%
Socialist Labor Peter McDermott 1,283 2.15%
Majority 7,738
Turnout
Democratic gain from Republican Swing
gollark: Yes, that is silly people being silly.
gollark: You're not really paying them for either as much as just the fact that they can do/make the thing you want and you are, presumably, willing to pay the price they ask for. Going around trying to judge someone else's "worth" in some way is problematic.
gollark: The learning time is amortized over all the other programming stuff they do, and it's not like they would somehow unlearn everything if you didn't pay more. Still, it is somewhat complicated and, er, possibly impossible, although if people want to do it (they regularly do complex things anyway if they're interesting) then why not.
gollark: Honestly it's not *that* practical a lot of the time because doing complex things is very hard and slow.
gollark: Oh, and reconnaissance, except not really because they have no sensors.

References

  1. "Congressional Quarterly's Guide to U.S. elections". Books.google.com. Retrieved July 13, 2020.
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