1880 United States presidential election in Alabama
The 1880 United States presidential election in Alabama took place on November 2, 1880, as part of the 1880 United States presidential election. Alabama voters chose ten representatives, or electors, to the Electoral College, who voted for president and vice president.[2]
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Turnout | 12.03% of the total population ![]() | |||||||||||||||||||||||||
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Elections in Alabama | ||||||||
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Alabama was won by General Winfield Scott Hancock (D–Pennsylvania), running with former Representative William Hayden English, with 59.99% of the popular vote, against Representative James Garfield (R-Ohio), running with the 10th chairman of the New York State Republican Executive Committee Chester A. Arthur, with 37.10% of the vote.[2]
Results
United States presidential election in Alabama, 1880[2] | ||||||||
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Party | Candidate | Running mate | Popular vote | Electoral vote | ||||
Count | % | Count | % | |||||
Democratic | Winfield Scott Hancock of Pennsylvania | William Hayden English of Indiana | 91,130 | 59.99% | 10 | 100.00% | ||
Republican | James Garfield of Ohio | Chester A. Arthur of New York | 56,350 | 37.10% | 0 | 0.00% | ||
Greenback | James B. Weaver of Iowa | Barzillai J. Chambers of Texas | 4,422 | 2.91% | 0 | 0.00% | ||
Total | 151,902 | 100.00% | 10 | 100.00% |
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References
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