1964 United States presidential election in Delaware

The 1964 United States presidential election in Delaware took place on November 3, 1964, as part of the 1964 United States presidential election. Delaware voters chose 3[2] representatives, or electors, to the Electoral College, who voted for president and vice president.

Main article: 1964 United States presidential election

United States presidential election in Delaware, 1964

November 3, 1964[1]

Nominee Lyndon B. Johnson Barry Goldwater Party Democratic Republican Home state Texas Arizona Running mate Hubert Humphrey William E. Miller Electoral vote 3 0 Popular vote 122,704 78,078 Percentage 61.0% 38.8%

County results Johnson   50-60%   60-70%

President before election Lyndon B. Johnson Democratic Elected President Lyndon B. Johnson Democratic

All 3 counties went blue, and Delaware was won by incumbent President Lyndon B. Johnson (D–Texas), with 60.95% of the popular vote, against Senator Barry Goldwater (R–Arizona), with 38.78% of the popular vote.[3][4]

Results

United States presidential election in Delaware, 1964

Party		Candidate	Votes	%
	Democratic	Lyndon B. Johnson (inc.)	122,704	60.95%
	Republican	Barry Goldwater	78,078	38.78%
	Write-in		538	0.27%
Total votes			201,320	100.00%

References

1. "United States Presidential election of 1964 - Encyclopædia Britannica". Retrieved May 29, 2017.
2. "1964 Election for the Forty-Fifth Term (1965-69)". Retrieved May 29, 2017.
3. "1964 Presidential General Election Results - Delaware". Retrieved May 29, 2017.
4. "The American Presidency Project - Election of 1964". Retrieved May 29, 2017.