1960 United States presidential election in Delaware

The 1960 United States presidential election in Delaware took place on November 8, 1960, as part of the 1960 United States presidential election. Delaware voters chose 3[2] representatives, or electors, to the Electoral College, who voted for president and vice president.

Main article: 1960 United States presidential election

United States presidential election in Delaware, 1960

November 8, 1960[1]

Nominee John F. Kennedy Richard Nixon Party Democratic Republican Home state Massachusetts California Running mate Lyndon B. Johnson Henry Cabot Lodge, Jr. Electoral vote 3 0 Popular vote 99,590 96,373 Percentage 50.6% 49.0%

County Results Kennedy   40-50%   50-60% Nixon   50-60%

President before election Dwight D. Eisenhower Republican Elected President John F. Kennedy Democratic

Delaware was won by Senator John F. Kennedy (D–Massachusetts), running with Senator Lyndon B. Johnson, with 50.63% of the popular vote against incumbent Vice President Richard Nixon (R–California), running with United States Ambassador to the United Nations Henry Cabot Lodge, Jr., with 49.00% of the popular vote.[3][4]

Results

United States presidential election in Delaware, 1960

Party		Candidate	Votes	%
	Democratic	John F. Kennedy	99,590	50.63%
	Republican	Richard Nixon	96,373	49.00%
	Write-in		720	0.37%
Total votes			196,683	100.00%

References

1. "United States Presidential election of 1960 - Encyclopædia Britannica". Retrieved June 7, 2017.
2. "1960 Election for the Forty-Fourth Term (1961-65)". Retrieved June 7, 2017.
3. "1960 Presidential General Election Results - Delaware". Retrieved June 7, 2017.
4. "The American Presidency Project - Election of 1960". Retrieved June 7, 2017.