1792 United States presidential election in Delaware

The 1792 United States presidential election in Delaware took place between November 2 and December 5, 1792 as part of the 1792 United States presidential election. The state legislature chose 3 members of the Electoral College, each of whom, under the provisions of the Constitution prior to the passage of the Twelfth Amendment, cast two votes for President.

Main article: 1792 United States presidential election

1792 United States presidential election in Delaware

November 2 – December 5, 1792

Nominee George Washington John Adams Party Nonpartisan Federalist Home state Virginia Massachusetts Electoral vote 3 3 Percentage 100% –

President before election George Washington Nonpartisanism Elected President George Washington Nonpartisanism

Delaware's 3 electors each cast 1 vote for the incumbent, George Washington, and 1 vote for John Adams, the incumbent Vice President.[1]

Results

United States presidential election in Delaware, 1792
Party		Candidate	Votes	Percentage	Electoral votes
	Nonpartisan	George Washington		100.00%	3
Totals				100.00%	3

References

1. Presidential Electoral Vote Count Dave Leip's Atlas of U.S. Presidential Elections.