1884 United States presidential election in Illinois

1884 United States presidential election in Illinois
	November 4, 1884
	November 4, 1884
President before election; Chester A. Arthur; Republican	Elected President ; Grover Cleveland; Democratic

The 1884 United States presidential election in Illinois took place on November 4, 1884, as part of the 1884 United States presidential election. Voters chose 22 representatives, or electors to the Electoral College, who voted for president and vice president.

Illinois voted for the Republican nominee, James G. Blaine, over the Democratic nominee, Grover Cleveland. Blaine won the state by a narrow margin of 3.74%.

Results

1884 United States presidential election in Illinois[1]
Party		Candidate	Running mate	Popular vote		Electoral vote
Party		Candidate	Running mate	Count	%	Count	%
	Republican	James Gillespie Blaine of Maine	John Alexander Logan of Illinois	337,469	50.17%	22	100.00%
	Democratic	Grover Cleveland of New York	Thomas Andrews Hendricks of Indiana	312,351	46.43%	0	0.00%
	Prohibition	John Pierce St. John of Kansas	William Daniel of Maryland	12,074	1.79%	0	0.00%
	Greenback	Benjamin Franklin Butler of Massachusetts	Absolom Madden West of Mississippi	10,776	1.60%	0	0.00%
Total				672,670	100.00%	22	100.00%

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