1888 United States presidential election in Massachusetts

The 1888 United States presidential election in Massachusetts took place on November 6, 1888, as part of the 1888 United States presidential election. Voters chose 14 representatives, or electors to the Electoral College, who voted for president and vice president.

Main article: 1888 United States presidential election
1888 United States presidential election in Massachusetts
November 6, 1888
Turnout71.7%[1] 2.4 pp
 
Nominee Benjamin Harrison Grover Cleveland
Party Republican Democratic
Home state Indiana New York
Running mate Levi P. Morton Allen G. Thurman
Electoral vote 14 0
Popular vote 183,892 151,590
Percentage 53.42% 44.04%
President before election

Grover Cleveland
Democratic

 Elected President

Benjamin Harrison
Republican

Elections in Massachusetts

Massachusetts voted for the Republican nominee, Benjamin Harrison, over the Democratic nominee, incumbent President Grover Cleveland. Harrison won the state by a narrow margin of 9.38%.

Results
1888 United States presidential election in Massachusetts[2]
Party Candidate Running mate Popular vote Electoral vote
Count % Count %
Republican Benjamin Harrison of Indiana Levi Parsons Morton of New York 183,892 53.42% 14 100.00%
Democratic Grover Cleveland of New York Allen Granberry Thurman of Ohio 151,590 44.04% 0 0.00%
Prohibition Clinton Bowen Fisk of New Jersey John Anderson Brooks of Missouri 8,701 2.53% 0 0.00%
N/A Others Others 60 0.02% 0 0.00%
Total 344,243 100.00% 14 100.00%

References
  1. Bicentennial Edition: Historical Statistics of the United States, Colonial Times to 1970, part 2, p. 1072.
  2. "1888 Presidential General Election Results - Massachusetts". U.S. Election Atlas. Retrieved 23 December 2013.
This article is issued from Wikipedia. The text is licensed under Creative Commons - Attribution - Sharealike. Additional terms may apply for the media files.