1840 United States presidential election in Massachusetts

The 1840 United States presidential election in Massachusetts took place between October 30 and December 2, 1840, as part of the 1840 United States presidential election. Voters chose 14 representatives, or electors to the Electoral College, who voted for President and Vice President.

Main article: 1840 United States presidential election
1840 United States presidential election in Massachusetts
October 30 - December 2, 1840
Turnout66.7%[1] 23.3 pp
 
Nominee William Henry Harrison Martin Van Buren
Party Whig Democratic
Home state Ohio New York
Running mate John Tyler none
Electoral vote 14 0
Popular vote 72,852 52,355
Percentage 57.44% 41.28%
President before election

Martin Van Buren
Democratic

 Elected President

William Henry Harrison
Whig

Elections in Massachusetts

Massachusetts voted for the Whig candidate, William Henry Harrison, over Democratic candidate Martin Van Buren. Harrison won Massachusetts by a margin of 16.16%.

Results
1840 United States presidential election in Massachusetts[2]
Party Candidate Running mate Popular vote Electoral vote
Count % Count %
Whig William Henry Harrison of Ohio John Tyler of Virginia 72,852 57.44% 14 100.00%
Democratic Martin Van Buren of New York Richard M. Johnson of Kentucky 52,355 41.28% 0 0.00%
Liberty James G. Birney of New York Thomas Earle of Pennsylvania 1,618 1.28% 0 0.00%
Total 126,825 100.00% 14 100.00%

References
  1. Bicentennial Edition: Historical Statistics of the United States, Colonial Times to 1970, part 2, p. 1072.
  2. "1840 Presidential General Election Results - Massachusetts". U.S. Election Atlas. Retrieved 23 December 2013.
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