1884 United States presidential election in Massachusetts

The 1884 United States presidential election in Massachusetts took place on November 4, 1884, as part of the 1884 United States presidential election. Voters chose 14 representatives, or electors to the Electoral College, who voted for president and vice president.

Main article: 1884 United States presidential election

1884 United States presidential election in Massachusetts

November 4, 1884
Turnout	69.3%[1] 1.9 pp
Nominee James G. Blaine Grover Cleveland Benjamin Franklin Butler Party Republican Democratic Greenback Home state Maine New York Massachusetts Running mate John A. Logan Thomas A. Hendricks Absolom Madden West Electoral vote 14 0 0 Popular vote 146,724 122,352 24,382 Percentage 48.36% 40.33% 8.04%
President before election Chester A. Arthur Republican Elected President Grover Cleveland Democratic

Massachusetts voted for the Republican nominee, James G. Blaine, over the Democratic nominee, Grover Cleveland. Blaine won the state by a narrow margin of 8.03%.

Results

1884 United States presidential election in Massachusetts[2]
Party		Candidate	Running mate	Popular vote		Electoral vote
				Count	%	Count	%
	Republican	James Gillespie Blaine of Maine	John Alexander Logan of Illinois	146,724	48.36%	14	100.00%
	Democratic	Grover Cleveland of New York	Thomas Andrews Hendricks of Indiana	122,352	40.33%	0	0.00%
	Greenback	Benjamin Franklin Butler of Massachusetts	Absolom Madden West of Mississippi	24,382	8.04%	0	0.00%
	Prohibition	John Pierce St. John of Kansas	William Daniel of Maryland	9,923	3.26%	0	0.00%
	N/A	Others	Others	2	0.01%	0	0.00%
Total				303,383	100.00%	14	100.00%

References

1. Bicentennial Edition: Historical Statistics of the United States, Colonial Times to 1970, part 2, p. 1072.
2. "1884 Presidential General Election Results - Massachusetts". U.S. Election Atlas. Retrieved 23 December 2013.