1864 United States presidential election in Indiana

The 1864 United States presidential election in Indiana took place on November 8, 1864, as part of the 1864 United States presidential election. Indiana voters chose thirteen representatives, or electors, to the Electoral College, who voted for president and vice president.[1]

Main article: 1864 United States presidential election

1864 United States presidential election in Indiana

November 8, 1864

Nominee Abraham Lincoln George B. McClellan Party National Union Democratic Home state Illinois New Jersey Running mate Andrew Johnson George H. Pendleton Electoral vote 13 0 Popular vote 150,422 130,233 Percentage 53.60% 46.40%

President before election Abraham Lincoln Republican Elected President Abraham Lincoln Republican

Indiana was won by the incumbent President Abraham Lincoln (R-Illinois), running with former Senator and Military Governor of Tennessee Andrew Johnson, with 53.60% of the popular vote, against the 4th Commanding General of the United States Army George B. McClellan (D–Pennsylvania), running with Representative George H. Pendleton, with 46.40% of the vote.[1]

Results

1864 United States presidential election in Indiana[1]
Party		Candidate	Running mate	Popular vote		Electoral vote
				Count	%	Count	%
	National Union	Abraham Lincoln of Illinois	Andrew Johnson of Tennessee	150,422	53.60%	13	100.00%
	Democratic	George B. McClellan of Pennsylvania	George H. Pendleton of Ohio	130,233	46.40%	0	0.00%
Total				280,655	100.00%	13	100.00%

References

1. "1864 Presidential Election Results Indiana".