1880 United States presidential election in Indiana
The 1880 United States presidential election in Indiana took place on November 2, 1880, as part of the 1880 United States presidential election. Voters chose 15 representatives, or electors to the Electoral College, who voted for president and vice president.
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| Elections in Indiana | ||||||
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Indiana voted for the Republican nominee, James A. Garfield, over the Democratic nominee, Winfield Scott Hancock. Garfield won the state by a narrow margin of 1.42%.
Results
| 1880 United States presidential election in Indiana[1] | ||||||||
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| Party | Candidate | Running mate | Popular vote | Electoral vote | ||||
| Count | % | Count | % | |||||
| Republican | James Abram Garfield of Ohio | Chester Alan Arthur of New York | 232,164 | 49.33% | 15 | 100.00% | ||
| Democratic | Winfield Scott Hancock of Pennsylvania | William Hayden English of Indiana | 225,522 | 47.91% | 0 | 0.00% | ||
| Greenback | James Baird Weaver of Iowa | Barzillai Jefferson Chambers of Texas | 12,986 | 2.76% | 0 | 0.00% | ||
| Total | 470,672 | 100.00% | 15 | 100.00% | ||||
Notes
References
State and district results of the 1880 United States presidential election | ||
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