1864 United States presidential election in Nevada
The 1864 United States presidential election in Nevada took place on November 8, 1864, as part of the 1864 United States presidential election. Nevada voters chose two representatives, or electors, to the Electoral College, who voted for president and vice president.[1]
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| Elections in Nevada | ||||||||
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Nevada voted in its first ever presidential election, having become the 36th state just eight days before the election on October 31. The state was won by the incumbent President Abraham Lincoln (R-Illinois), running with former Senator and Military Governor of Tennessee Andrew Johnson, with 59.84% of the popular vote, against the 4th Commanding General of the United States Army George B. McClellan (D–Pennsylvania), running with Representative George H. Pendleton, with 40.16% of the vote.[1]
Due to the abstention of one of Nevada's three electors, this election is tied for the fewest total electoral votes cast by a state or area in a presidential election with the 1820 election in Mississippi, where one elector died before the Electoral College convened, and the District of Columbia in 2000, which also saw an elector abstain and only two votes go to the winner.
Results
| 1864 United States presidential election in Nevada[1] | ||||||||
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| Party | Candidate | Running mate | Popular vote | Electoral vote | ||||
| Count | % | Count | % | |||||
| National Union | Abraham Lincoln of Illinois | Andrew Johnson of Tennessee | 9,826 | 59.84% | 2 | 100.00% | ||
| Democratic | George B. McClellan of Pennsylvania | George H. Pendleton of Ohio | 6,594 | 40.16% | 0 | 0.00% | ||
| Total | 16,420 | 100.00% | 2 | 100.00% | ||||
