1908 United States presidential election in Indiana

The 1908 United States presidential election in Indiana took place on November 3, 1908. Voters chose 15 representatives, or electors to the Electoral College, who voted for president and vice president.

Main article: 1908 United States presidential election

1908 United States presidential election in Indiana

November 3, 1908

Nominee William Howard Taft William Jennings Bryan Party Republican Democratic Home state Ohio Nebraska Running mate James S. Sherman John Worth Kern Electoral vote 15 0 Popular vote 348,993 338,262 Percentage 48.40% 46.91%

President before election Theodore Roosevelt Republican Elected President William Howard Taft Republican

Indiana voted for the Republican nominee, Secretary of War William Howard Taft, over the Democratic nominee, former U.S. Representative William Jennings Bryan. Taft won the state by a narrow margin of 1.49%.

Results

1908 United States presidential election in Indiana[1]
Party		Candidate	Running mate	Popular vote		Electoral vote
				Count	%	Count	%
	Republican	William Howard Taft of Ohio	James Schoolcraft Sherman of New York	348,993	48.40%	15	100.00%
	Democratic	William Jennings Bryan of Nebraska	John Worth Kern of Indiana	338,262	46.91%	0	0.00%
	Prohibition	Eugene Wilder Chafin of Illinois	Aaron Sherman Watkins of Ohio	18,845	2.50%	0	0.00%
	Socialist	Eugene Victor Debs of Indiana	Benjamin Hanford of New York	13,476	1.87%	0	0.00%
	People's	Thomas Edward Watson of Georgia	Samuel Williams of Indiana	1,193	0.17%	0	0.00%
	Socialist Labor	August Gillhaus of New York	Donald L. Munro of Virginia	643	0.09%	0	0.00%
	Independence	Thomas Louis Hisgen of Massachusetts	John Temple Graves of Georgia	514	0.07%	0	0.00%
Total				721,126	100.00%	15	100.00%

References

1. "1908 Presidential General Election Results - Indiana". U.S. Election Atlas. Retrieved 23 December 2013.