1998 United States House of Representatives elections in Indiana
The 1998 congressional elections in Indiana were elections for Indiana's delegation to the United States House of Representatives, which occurred along with congressional elections nationwide on November 3, 1998. Republicans held a majority of Indiana's delegation over the Democrats, 6-4. Representatives were elected using the U.S. congressional districts based on the 1990 U.S. Census.
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All 10 Indiana seats to the United States House of Representatives | |||||||||||||||||||||||||
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| Elections in Indiana | ||||||
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Results
The following are the final results from the Secretary of State of Indiana.[1]
Overview
| United States House of Representatives elections in Indiana, 1998[2] | |||||
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| Party | Votes | Percentage | Seats | +/– | |
| Republican | 861,951 | 54.70% | 6 | - | |
| Democratic | 673,322 | 42.73% | 4 | - | |
| Libertarian | 40,507 | 2.57% | 0 | - | |
| Others | 91 | <0.01% | 0 | - | |
| Totals | 1,575,871 | 100.00% | 10 | - | |
See also
- United States House of Representatives elections, 1998
References
- "United States Representative". Indiana of Secretary of State. Retrieved 2008-11-09.
- http://clerk.house.gov/member_info/electioninfo/index.aspx
| Preceded by 1996 elections |
United States House elections in Indiana 1998 |
Succeeded by 2000 elections |
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