Poinçon-lès-Larrey
Poinçon-lès-Larrey is a commune in the Côte-d'Or department in eastern France.
Poinçon-lès-Larrey | |
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A general view of Poinçon-lès-Larrey | |
Location of Poinçon-lès-Larrey ![]() | |
![]() ![]() Poinçon-lès-Larrey ![]() ![]() Poinçon-lès-Larrey | |
Coordinates: 47°53′01″N 4°27′18″E | |
Country | France |
Region | Bourgogne-Franche-Comté |
Department | Côte-d'Or |
Arrondissement | Montbard |
Canton | Châtillon-sur-Seine |
Government | |
• Mayor (2008–2014) | André Gerard |
Area 1 | 10.42 km2 (4.02 sq mi) |
Population (2017-01-01)[1] | 194 |
• Density | 19/km2 (48/sq mi) |
Time zone | UTC+01:00 (CET) |
• Summer (DST) | UTC+02:00 (CEST) |
INSEE/Postal code | 21488 /21330 |
Elevation | 216–328 m (709–1,076 ft) (avg. 228 m or 748 ft) |
1 French Land Register data, which excludes lakes, ponds, glaciers > 1 km2 (0.386 sq mi or 247 acres) and river estuaries. |
Population
Year | Pop. | ±% |
---|---|---|
1962 | 228 | — |
1968 | 230 | +0.9% |
1975 | 235 | +2.2% |
1982 | 236 | +0.4% |
1990 | 199 | −15.7% |
1999 | 196 | −1.5% |
2008 | 201 | +2.6% |
gollark: Of course.
gollark: I'm not entirely sure how, but it seems to construct a tree/maybe deterministic finite automaton/finite state machine/I don't know theoretical CS which matches anagrams and unmatches unanagrams.
gollark: ```pythonimport collectionsdef do_thing(s): if len(s) == 1: return { s[0]: True } out = {} for i, c in enumerate(s): without = s[:i] + s[i + 1:] things = do_thing(without) out[c] = things return outdef match(r, s): print(r) c = r for i, x in enumerate(s): print(x) try: c = c[x] if c == True: if i + 1 == len(s): return True # full match else: return False # characters remain except KeyError: return False # no match return False # incomplete matchentry = lambda a, b: match(do_thing(a.lower().replace(" ", "")), b.lower().replace(" ", ""))```Here is my entry (pending a port to osmarkslisp™️). This is definitely my entry.
gollark: I wish to use Mathematica in my code. Please install it. DO NOT READ, ubq.
gollark: I have a "great" way to do this which I think takes O(n²) space-time-beeite.
See also
References
- "Populations légales 2017". INSEE. Retrieved 6 January 2020.
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