Hardin Township, Pike County, Illinois
Hardin Township is located in Pike County, Illinois. As of the 2010 census, its population was 212 and it contained 105 housing units.[2]
Hardin Township | |
---|---|
Township | |
![]() Location in Pike County | |
![]() Pike County's location in Illinois | |
Country | United States |
State | Illinois |
County | Pike |
Established | November 8, 1853 |
Area | |
• Total | 37.41 sq mi (96.9 km2) |
• Land | 37.39 sq mi (96.8 km2) |
• Water | 0.03 sq mi (0.08 km2) 0.08% |
Population (2010) | |
• Estimate (2016)[1] | 206 |
• Density | 5.7/sq mi (2.2/km2) |
Time zone | UTC-6 (CST) |
• Summer (DST) | UTC-5 (CDT) |
FIPS code | 17-149-32863 |
Geography
According to the 2010 census, the township encompasses an area of 37.41 square miles (96.9 km2), of which 37.39 square miles (96.8 km2) (or 99.95%) is land and 0.03 square miles (0.078 km2) (or 0.08%) is water.[2]
Demographics
Historical population | |||
---|---|---|---|
Census | Pop. | %± | |
Est. 2016 | 206 | [1] | |
U.S. Decennial Census[3] |
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References
- "Population and Housing Unit Estimates". Retrieved June 9, 2017.
- "Population, Housing Units, Area, and Density: 2010 - County -- County Subdivision and Place -- 2010 Census Summary File 1". United States Census. Archived from the original on 2020-02-12. Retrieved 2013-05-28.
- "Census of Population and Housing". Census.gov. Retrieved June 4, 2016.
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