2016 Qatar ExxonMobil Open – Doubles
Juan Mónaco and Rafael Nadal were the defending champions, but Mónaco could not participate due to an injury. Nadal played alongside Fernando Verdasco, but lost in the first round to Teymuraz Gabashvili and Albert Ramos-Viñolas.
Feliciano López and Marc López won the title, defeating Philipp Petzschner and Alexander Peya in the final, 6–4, 6–3.
Doubles | |
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2016 Qatar ExxonMobil Open | |
Champions | ![]() ![]() |
Runners-up | ![]() ![]() |
Final score | 6–4, 6–3 |
Seeds
Jean-Julien Rojer / Horia Tecău (Semifinals) Jamie Murray / Bruno Soares (Semifinals) Feliciano López / Marc López (Champions) Philipp Petzschner / Alexander Peya (Final)
Draw
Key
- Q = Qualifier
- WC = Wild Card
- LL = Lucky Loser
- Alt = Alternate
- SE = Special Exempt
- PR = Protected Ranking
- ITF = ITF entry
- JE = Junior Exempt
- w/o = Walkover
- r = Retired
- d = Defaulted
Draw
First Round | Quarterfinals | Semifinals | Final | ||||||||||||||||||||||||
1 | ![]() ![]() | 77 | 6 | ||||||||||||||||||||||||
![]() ![]() | 64 | 3 | 1 | ![]() ![]() | 6 | 6 | |||||||||||||||||||||
![]() ![]() | 77 | 4 | [9] | ![]() ![]() | 1 | 1 | |||||||||||||||||||||
![]() ![]() | 64 | 6 | [11] | 1 | ![]() ![]() | 65 | 2 | ||||||||||||||||||||
4 | ![]() ![]() | 6 | 6 | 4 | ![]() ![]() | 77 | 6 | ||||||||||||||||||||
WC | ![]() ![]() | 1 | 1 | 4 | ![]() ![]() | 6 | 6 | ||||||||||||||||||||
![]() ![]() | 77 | 6 | ![]() ![]() | 2 | 4 | ||||||||||||||||||||||
![]() ![]() | 64 | 3 | 4 | ![]() ![]() | 4 | 3 | |||||||||||||||||||||
![]() ![]() | 78 | 6 | 3 | ![]() ![]() | 6 | 6 | |||||||||||||||||||||
![]() ![]() | 66 | 1 | ![]() ![]() | 2 | 77 | [6] | |||||||||||||||||||||
![]() ![]() | 65 | 4 | 3 | ![]() ![]() | 6 | 63 | [10] | ||||||||||||||||||||
3 | ![]() ![]() | 77 | 6 | 3 | ![]() ![]() | 3 | 6 | [10] | |||||||||||||||||||
![]() ![]() | 6 | 6 | 2 | ![]() ![]() | 6 | 3 | [5] | ||||||||||||||||||||
WC | ![]() ![]() | 2 | 2 | ![]() ![]() | 65 | 4 | |||||||||||||||||||||
![]() ![]() | 3 | 3 | 2 | ![]() ![]() | 77 | 6 | |||||||||||||||||||||
2 | ![]() ![]() | 6 | 6 |
gollark: No it's not.
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gollark: Well, sure, but this saves you from having to actually define the arity on every function manually.
gollark: Though you could *also* just do that wherever you actually need that arity value.
gollark: Sure, I guess.
References
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