1996 United States presidential election in Alaska

The 1996 United States presidential election in Alaska took place on November 7, 1996, as part of the 1996 United States presidential election. Voters chose representatives, or electors to the Electoral College, who voted for president and vice president.

Main article: 1996 United States presidential election

1996 United States presidential election in Alaska

November 5, 1996

Nominee Bob Dole Bill Clinton Ross Perot Party Republican Democratic Reform Home state Kansas Arkansas Texas Running mate Jack Kemp Al Gore Pat Choate Electoral vote 3 0 0 Popular vote 122,746 80,380 26,333 Percentage 50.80% 33.27% 10.90%

Borough Results Dole   40-50%   50-60%   60-70% Clinton   30-40%   40-50%   50-60%

President before election Bill Clinton Democratic Elected President Bill Clinton Democratic

Alaska was won by Senator Bob Dole (R-KS), with Dole winning 50.80% to 33.27% over President Bill Clinton (D) by a margin of 17.53%.[1] Billionaire businessman Ross Perot (Reform-TX) finished in third, with 10.9% of the popular vote.

With 50.8% of the popular vote, Alaska proved to be Dole's fifth strongest state in the 1996 election after Utah, Kansas, Nebraska and Idaho.[2]

Results

1996 United States presidential election in Alaska
Party		Candidate	Running mate	Votes	Percentage	Electoral votes
	Republican	Robert Dole	Jack Kemp	122,746	50.80%	3
	Democratic	Bill Clinton (incumbent)	Al Gore	80,380	33.27%	0
	Reform	Ross Perot	Patrick Choate	26,333	10.90%	0
	Green Party	Ralph Nader	Winona LaDuke	7,597	3.14%	0
	Libertarian	Harry Browne	Jo Jorgensen	2,276	0.94%	0
	U.S. Taxpayers' Party	Howard Phillips	Herbert Titus	925	0.38%	0
	Natural Law	Dr. John Hagelin	Dr. V. Tompkins	729	0.30%	0
	Write-ins			634	0.26%	0
Totals				241,620	100.0%	3

References

1. Dave Leip's Atlas of United States Presidential Election Results - 1996 Alaska Results
2. "1996 Presidential Election Statistics". Dave Leip’s Atlas of U.S. Presidential Elections. Retrieved 2018-03-05.