1864 United States presidential election in Indiana
The 1864 United States presidential election in Indiana took place on November 8, 1864, as part of the 1864 United States presidential election. Indiana voters chose thirteen representatives, or electors, to the Electoral College, who voted for president and vice president.[1]
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| Elections in Indiana | ||||||
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Indiana was won by the incumbent President Abraham Lincoln (R-Illinois), running with former Senator and Military Governor of Tennessee Andrew Johnson, with 53.60% of the popular vote, against the 4th Commanding General of the United States Army George B. McClellan (D–Pennsylvania), running with Representative George H. Pendleton, with 46.40% of the vote.[1]
Results
| 1864 United States presidential election in Indiana[1] | ||||||||
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| Party | Candidate | Running mate | Popular vote | Electoral vote | ||||
| Count | % | Count | % | |||||
| National Union | Abraham Lincoln of Illinois | Andrew Johnson of Tennessee | 150,422 | 53.60% | 13 | 100.00% | ||
| Democratic | George B. McClellan of Pennsylvania | George H. Pendleton of Ohio | 130,233 | 46.40% | 0 | 0.00% | ||
| Total | 280,655 | 100.00% | 13 | 100.00% | ||||
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