1940 United States Senate election in Vermont

The 1940 United States Senate election in Vermont took place on November 5, 1940. Incumbent Republican Warren Austin successfully ran for re-election to another term in the United States Senate, defeating Democratic candidate Ona S. Searles. Austin would resign in August 1946 to become United States Ambassador to the United Nations; Ralph Flanders was appointed to replace him and went on to win election to a full term in 1946.

1940 United States Senate election in Vermont
November 5, 1940 (1940-11-05)
 
Nominee Warren Austin Ona Searles
Party Republican Democratic
Popular vote 93,283 47,101
Percentage 66.4% 33.6%
U.S. senator before election

Warren Austin
Republican

 Elected U.S. Senator

Warren Austin
Republican

Elections in Vermont

Republican primary

Results
Republican primary results[1]
Party Candidate Votes % ±
Republican Warren Austin (inc.) 60,603 99.9
Republican Other 65 0.1
Total votes '60,668' '100'

Democratic primary

Results
Democratic primary results[1]
Party Candidate Votes % ±
Democratic Ona S. Searles 5,340 99.4
Democratic Other 33 0.6
Total votes '5,373' '100'

General election

Results
United States Senate election in Vermont, 1940[2]
Party Candidate Votes % ±
Republican Warren Austin (inc.) 93,283 66.4
Democratic Ona S. Searles 47,101 33.6
Total votes '140,384' '100'

See also
  • United States Senate elections, 1940 and 1941

References
  1. "Primary Election Results" (PDF). Office of the Vermont Secretary of State. Retrieved 16 June 2015.
  2. "General Election Results - U.S. Senator - 1914-2014" (PDF). Office of the Vermont Secretary of State. Retrieved 16 June 2015.
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