1940 Iowa gubernatorial election

The 1940 Iowa gubernatorial election was held on November 5, 1940. Incumbent Republican George A. Wilson defeated Democratic nominee John K. Valentine with 52.72% of the vote.

1940 Iowa gubernatorial election
November 7, 1940
 
Nominee George A. Wilson John K. Valentine
Party Republican Democratic
Popular vote 620,480 553,941
Percentage 52.72% 47.07%
Governor before election

George A. Wilson
Republican

 Elected Governor

George A. Wilson
Republican

Elections in Iowa

Primary elections

Primary elections were held on June 3, 1940.[1]

Democratic primary

Candidates

Results
Democratic primary results[1]
Party Candidate Votes %
Democratic John K. Valentine 70,233 57.88
Democratic Edward Breen 51,112 42.12
Total votes 121,345 100.00

Republican primary

Candidates

Results
Republican primary results[1]
Party Candidate Votes %
Republican George A. Wilson 165,176 49.66
Republican H. R. Gross 146,395 44.01
Republican Irving H. Knudson 21,039 6.33
Total votes 332,610 100.00

General election

Candidates

Major party candidates

  • George A. Wilson, Republican
  • John K. Valentine, Democratic

Other candidates

  • M. M. Heptonstall, Prohibition
  • Charles Speck, Communist

Results
1940 Iowa gubernatorial election[2]
Party Candidate Votes % ±
Republican George A. Wilson 620,480 52.72%
Democratic John K. Valentine 553,941 47.07%
Prohibition M. M. Heptonstall 1,289 0.11%
Communist Charles Speck 1,230 0.11%
Majority 66,539
Turnout
Republican hold Swing

References
  1. "Summary of Official Canvass of Votes Cast in Iowa Primary Election" (PDF). Secretary of State of Iowa. 1940. Retrieved April 18, 2020.
  2. "Summary of Official Canvass of Votes Cast in Iowa General Election" (PDF). Secretary of State of Iowa. 1940. Retrieved April 18, 2020.
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