1940 United States presidential election in West Virginia

The 1940 United States presidential election in West Virginia took place on November 5, 1940, as part of the 1940 United States presidential election. West Virginia voters chose eight[2] representatives, or electors, to the Electoral College, who voted for president and vice president.

Main article: 1940 United States presidential election

1940 United States presidential election in West Virginia

November 5, 1940[1]
All 8 West Virginia votes to the Electoral College
Nominee Franklin D. Roosevelt Wendell Willkie Party Democratic Republican Home state New York Indiana Running mate Henry A. Wallace Charles L. McNary Electoral vote 8 0 Popular vote 495,662 372,414 Percentage 57.1% 42.9%
County Results Roosevelt   50-60%   60-70% Willkie   50-60%   60-70%   70-80%
President before election Franklin D. Roosevelt Democratic Elected President Franklin D. Roosevelt Democratic

West Virginia was won by incumbent President Franklin D. Roosevelt (D–New York), running with Secretary Henry A. Wallace, with 57.10% of the popular vote, against Wendell Willkie (R–Indiana), running with Minority Leader Charles L. McNary, with 42.90% of the popular vote.[3][4]

Results

1940 United States presidential election in West Virginia

Party		Candidate	Votes	%
	Democratic	Franklin D. Roosevelt (inc.)	495,662	57.10%
	Republican	Wendell Willkie	372,414	42.90%
Total votes			868,076	100%

References

1. "United States Presidential election of 1940 - Encyclopædia Britannica". Retrieved December 19, 2018.
2. "1940 Election for the Thirty-ninth Term (1941-45)". Retrieved December 19, 2018.
3. "1940 Presidential General Election Results - West Virginia". Retrieved December 19, 2018.
4. "The American Presidency Project - Election of 1940". Retrieved December 19, 2018.