1916 Iowa gubernatorial election

The 1916 Iowa gubernatorial election was held on November 7, 1916. Republican nominee William L. Harding defeated Democratic nominee Edwin T. Meredith with 61.03% of the vote.

1916 Iowa gubernatorial election
November 7, 1916
 
Nominee William L. Harding Edwin T. Meredith
Party Republican Democratic
Popular vote 313,586 186,832
Percentage 61.03% 36.36%
Governor before election

George W. Clarke
Republican

 Elected Governor

William L. Harding
Republican

Elections in Iowa

General election

Candidates

Major party candidates

  • William L. Harding, Republican
  • Edwin T. Meredith, Democratic

Other candidates

  • John W. Bennett, Socialist
  • Oren D. Ellett, Prohibition
  • Stephen H. Bashor, Progressive
  • Arthur S. Dowler, Socialist Labor

Results
1916 Iowa gubernatorial election[1]
Party Candidate Votes % ±
Republican William L. Harding 313,586 61.03%
Democratic Edwin T. Meredith 186,832 36.36%
Socialist John W. Bennett 8,200 1.60%
Prohibition Oren D. Ellett 2,880 0.56%
Progressive Stephen H. Bashor 2,035 0.40%
Socialist Labor Arthur S. Dowler 315 0.06%
Majority 126,754
Turnout
Republican hold Swing

References
  1. "Guide to U.S. Elections". Books.google.com. Retrieved July 2, 2020.
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