Oak Grove Township, Benton County, Indiana

Oak Grove Township is one of eleven townships in Benton County, Indiana. As of the 2010 census, its population was 1,581 and it contained 705 housing units.[3] It was one of the first three townships originally created by the county's commissioners in 1840.[4] It takes its name from White Oak Grove which grew southwest of Oxford.[5]

Oak Grove Township
Location of Oak Grove Township in Benton County
Coordinates: 40°31′09″N 87°15′54″W
CountryUnited States
StateIndiana
CountyBenton
OrganizedJuly 1840
Government
  TypeIndiana township
Area
  Total35.53 sq mi (92.0 km2)
  Land35.51 sq mi (92.0 km2)
  Water0.02 sq mi (0.05 km2)
Elevation748 ft (228 m)
Population
 (2010)
  Total1,581
  Density44.5/sq mi (17.2/km2)
Time zoneUTC-5 (EST)
  Summer (DST)UTC-4 (EDT)
FIPS code18-55620[2]
GNIS feature ID453681

Geography

According to the 2010 census, the township has a total area of 35.53 square miles (92.0 km2), of which 35.51 square miles (92.0 km2) (or 99.94%) is land and 0.02 square miles (0.052 km2) (or 0.06%) is water.[3]

Cities and towns

Unincorporated towns

Adjacent townships

Major highways

Cemeteries

The township contains two cemeteries: Justus and Oxford.

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References

  1. "US Board on Geographic Names". United States Geological Survey. 2007-10-25. Retrieved 2008-01-31.
  2. "U.S. Census website". United States Census Bureau. Retrieved 2008-01-31.
  3. "Population, Housing Units, Area, and Density: 2010 - County -- County Subdivision and Place -- 2010 Census Summary File 1". United States Census. Archived from the original on 2020-02-12. Retrieved 2013-05-10.
  4. Birch, Jesse Setlington (1942) [1928]. History of Benton County and Historic Oxford. Oxford, Indiana: Craw & Craw, Inc. p. 20.
  5. Andreas, Alfred Theodore (1876). "Benton County". Illustrated Historical Atlas of the State of Indiana. Chicago: Baskin, Forster & Company.
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