1998 ENKA Open – Doubles

Meike Babel and Laurence Courtois won in the final 6–0, 6–2 against Åsa Carlsson and Florencia Labat in the doubles of the 1998 ENKA Open.

Doubles
1998 ENKA Open
Champions Meike Babel
Laurence Courtois
Runners-up Åsa Carlsson
Florencia Labat
Final score6–0, 6–2

Seeds

Champion seeds are indicated in bold text while text in italics indicates the round in which those seeds were eliminated.

  1. Sabine Appelmans / Els Callens (Quarterfinals)
  2. Meike Babel / Laurence Courtois (Champions)
  3. Radka Bobková / Caroline Schneider (First Round)
  4. Olga Barabanschikova / Tina Križan (Quarterfinals)

Draw

Key
First Round Quarterfinals Semifinals Final
1 S Appelmans
E Callens 		4 6 7
  A Cocheteux
É Loit 		6 3 5 1 S Appelmans
E Callens 		3 4  
  S Noorlander
C Papadáki 		6 6     S Noorlander
C Papadáki 		6 6  
  H Inoue
S Pitkowski 		2 3     S Noorlander
C Papadáki 		3 6 6
3 R Bobková
C Schneider 		3 4     Å Carlsson
F Labat 		6 4 7
  Å Carlsson
F Labat 		6 6     Å Carlsson
F Labat 		6 6  
Q J Kandarr
F Lubiani 		6 6   Q J Kandarr
F Lubiani 		1 1  
  L Němečková
C Torrens Valero 		4 4     Åsa Carlsson
Florencia Labat 		0 2  
  A Lombardi
G Riera Roura 		4 2   2 Meike Babel
Laurence Courtois 		6 6  
  E Kulikovskaya
O Lugina 		6 6     E Kulikovskaya
O Lugina 		6 7  
WC H Gorur
C Konuk 		1 2   4 O Barabanschikova
T Križan 		0 5  
4 O Barabanschikova
T Križan 		6 6     E Kulikovskaya
O Lugina 		3 3  
  R Sandu
J Wöhr 		3 1   2 M Babel
L Courtois 		6 6  
  A Canepa
T Garbin 		6 6     A Canepa
T Garbin 		2 0  
  R Jensen
D Jones 		1 3   2 M Babel
L Courtois 		6 6  
2 M Babel
L Courtois 		6 6  
gollark: (10-4)/(3-1)?
gollark: ... are you sure?
gollark: Divide the difference in Y by the difference in X, yes.
gollark: Take two of the points, subtract one's Y coordinate from the other one's Y coordinate, and do the same for the X coordinates, and divide the difference in Y coords by the difference in X coords.
gollark: <@379441093558927391> I'm assuming that what you want to do is find the equation of the straight line going through those points. So to do that you need the gradient.
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