1906 Wyoming gubernatorial election

The Wyoming gubernatorial election of 1906 took place on November 6, 1906. The Republican incumbent Bryant Butler Brooks defeated the Democratic Stephen A. D. Keister with 60.20% of the vote.

Wyoming gubernatorial election, 1906

November 6, 1906 (1906-11-06)
Turnout	29.29% of Total Population 4.11
Nominee Bryant Butler Brooks Stephen A. D. Keister Party Republican Democratic Popular vote 16,317 9,444 Percentage 60.20% 34.85%
County Result
Governor before election Bryant Butler Brooks Republican Elected Governor Bryant Butler Brooks Republican

Results

Wyoming gubernatorial election, 1906[1]

Party		Candidate	Votes	%
	Republican	Bryant Butler Brooks	16,317	60.20%
	Democratic	Stephen A. D. Keister	9,444	34.85%
	Socialist	William L. O'Neill	1,236	4.56%
	Independent	George W. Blain	106	0.39%
Total votes			27,103	100%

Results by county

County	Brooks	Votes	Keister	Votes	O'Neill	Votes	Blain	Votes
Uinta	59.34%	2,259	28.24%	1,075	12.19%	465	0.24%	9
Big Horn	66.00%	1,807	32.18%	881	1.57%	43	0.26%	7
Fremont	35.51%	722	62.52%	1,271	1.43%	29	0.54%	11
Sweetwater	59.83%	1,010	32.46%	548	7.41%	125	0.30%	5
Sheridan	54.92%	1,411	37.02%	951	7.82%	201	0.23%	6
Johnson	56.54%	666	42.44%	500	0.93%	11	0.08%	1
Natrona	63.00%	664	37.00%	390	0.00%	0	0.00%	0
Carbon	65.82%	1,579	30.47%	548	3.50%	84	0.21%	5
Crook	64.40%	747	31.29%	363	4.05%	47	0.26%	3
Weston	70.18%	633	29.16%	263	0.55%	5	0.11%	1
Converse	68.57%	1,023	27.95%	417	1.27%	19	2.21%	33
Albany	57.45%	1,342	32.83%	767	8.73%	204	0.98%	23
Laramie	65.49%	2,454	34.45%	1,287	0.11%	4	0.05%	2

References

1. "Wyoming gubernatorial election, 1906".