1868 United States presidential election in Missouri

The 1868 United States presidential election in Missouri took place on November 3, 1868, as part of the 1868 United States presidential election. Missouri voters chose eleven representatives, or electors, to the Electoral College, who voted for president and vice president.[1]

Main article: 1868 United States presidential election

United States presidential election in Missouri, 1868

November 3, 1868

Nominee Ulysses S. Grant Horatio Seymour Party Republican Democratic Home state Ohio New York Running mate Schuyler Colfax Francis Preston Blair Jr. Electoral vote 11 0 Popular vote 86,860 65,628 Percentage 56.96% 43.04%

President before election Andrew Johnson Democratic Elected President Ulysses S. Grant Republican

Missouri was won by Ulysses S. Grant, formerly the 6th Commanding General of the United States Army (R-Ohio), running with Speaker of the House Schuyler Colfax, with 56.96% of the popular vote, against the 18th governor of New York, Horatio Seymour (D–New York), running with former Senator Francis Preston Blair, Jr., with 43.04% of the vote.[1]

Grant's victory in Missouri made him the first Republican presidential candidate to win the state, although President Abraham Lincoln had won the state on the National Union ticket in 1864. Grant would also be the only Republican to carry the state until Theodore Roosevelt won it in 1904.

Results

United States presidential election in Missouri, 1868[1]
Party		Candidate	Running mate	Popular vote		Electoral vote
				Count	%	Count	%
	Republican	Ulysses S. Grant of Ohio	Schuyler Colfax of Indiana	86,860	56.96%	11	100.00%
	Democratic	Horatio Seymour of New York	Francis Preston Blair, Jr. of Missouri	65,628	43.04%	0	0.00%
Total				152,488	100.00%	11	100.00%

References

1. "1868 Presidential Election Results Missouri".