Archery at the 1991 Pan American Games
This page shows the results of the Archery Competition at the 1991 Pan American Games, held from August 2 to August 18, 1991, in Havana, Cuba.
Archery at the XI Pan American Games | |
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«1987 1995» |
Men's competition
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Recurve 70 m
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Recurve 90 m
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Women's competition
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Recurve 50 m
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Recurve 60 m
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Recurve 70 m
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Recurve Teams
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Medal table
Place | Nation | ![]() |
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Total |
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1 | ![]() |
12 | 9 | 0 | 21 |
2 | ![]() |
0 | 2 | 10 | 12 |
3 | ![]() |
0 | 1 | 2 | 3 |
Total | 12 | 12 | 12 | 36 |
gollark: There is in fact no escape.
gollark: Gæh?
gollark: As planned.
gollark: <@332271551481118732> <@332271551481118732> <@332271551481118732> <@332271551481118732> <@332271551481118732> <@332271551481118732> <@332271551481118732> <@332271551481118732> <@332271551481118732> <@332271551481118732> <@332271551481118732> <@332271551481118732> <@332271551481118732> <@332271551481118732> <@332271551481118732> <@332271551481118732> <@332271551481118732> <@332271551481118732> <@332271551481118732> <@332271551481118732> <@332271551481118732> <@332271551481118732> <@332271551481118732> <@332271551481118732> <@332271551481118732>
gollark: Assume there are integers x, y satisfying x²-y²=2(x-y)(x+y)=2x-y, x+y are both integers because they are a sum/difference of integersx, y >= 0 because (-x)²=x² so just ignore negative solutions since they only exist if a positive one does2 has the factors 2,1 so x-y, x+y must be 1, 2 in some orderx-y, x+y differ by 2yx-y, x+y differ by 12y=1y=½But y is an integer
See also
References
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