2019 Reinert Open – Singles

Olga Danilović was the defending champion, but chose not to participate.[1]

Singles
2019 Reinert Open
Champion Nina Stojanović
Runner-up Katharina Hobgarski
Final score6–0, 7–5

Nina Stojanović won the title, defeating Katharina Hobgarski in the final, 6–0, 7–5.

Seeds

  1. Bibiane Schoofs (Semifinals)
  2. Barbara Haas (First round)
  3. Richèl Hogenkamp (First round)
  4. Ankita Raina (Second round)
  5. Viktoriya Tomova (First round)
  6. Anna Bondár (Second round)
  7. Irina Bara (Quarterfinals)
  8. Valentini Grammatikopoulou (Second round)

Draw

Key

Finals

Semifinals Final
          
1 Bibiane Schoofs 2 5
  Katharina Hobgarski 6 7
  Katharina Hobgarski 0 5
  Nina Stojanović 6 7
  Nina Stojanović 6 6
WC Jule Niemeier 4 3

Top half

First Round Second Round Quarterfinals Semifinals
1 B Schoofs 4 6 7
  M Di Giuseppe 6 3 5 1 B Schoofs 77 6
  J Fourlis 65 6 4 M Benoît 62 3
  M Benoît 77 1 6 1 B Schoofs 7 4 6
WC J Wachaczyk 1 2 L Hradecká 5 6 2
  L Hradecká 6 6 L Hradecká 3 6 6
Q C Scholl 5 67 6 A Bondár 6 3 2
6 A Bondár 7 79 1 B Schoofs 2 5
4 A Raina 6 77 K Hobgarski 6 7
  N Kostić 1 61 4 A Raina 3 1
  K Hobgarski 2 711 6 K Hobgarski 6 6
  K von Deichmann 6 69 3 K Hobgarski 3 6 6
Q N Dascălu 5 4 L Chirico 6 4 2
  L Chirico 7 6 L Chirico 6 2 77
Q A Shoshyna 2 2 8 V Grammatikopoulou 4 6 63
8 V Grammatikopoulou 6 6

Bottom half

First Round Second Round Quarterfinals Semifinals
5 V Tomova 4 6 4
Q T Pereira 6 3 6 Q T Pereira 6 6
  O Govortsova 6 6 O Govortsova 2 4
Q A Anshba 2 4 Q T Pereira 1 4
  S Wagner 6 0 4 N Stojanović 6 6
  N Stojanović 3 6 6 N Stojanović 6 6
Q C Ferrando 6 6 Q C Ferrando 2 1
3 R Hogenkamp 4 2 N Stojanović 6 6
7 I Bara 6 6 WC J Niemeier 4 3
Q E Makarova 2 4 7 I Bara 4 6 6
WC K Gerlach 3 5 E Kostova 6 3 0
  E Kostova 6 7 7 I Bara 2 3
WC J Niemeier 7 6 WC J Niemeier 6 6
Q A Dețiuc 5 0 WC J Niemeier 6 0r
WC J Steur 77 77 WC J Steur 3 0
2 B Haas 65 63
gollark: Probably.
gollark: ++remind 9h abr highlight maybe?
gollark: Possibly not suitable for crypto.
gollark: There are probably ways to get *specific types* of prime of some kind.
gollark: I know about the "quadratic number field sieve" but it just does factoring.

References

  1. "W60 Versmold". www.itftennis.com.
This article is issued from Wikipedia. The text is licensed under Creative Commons - Attribution - Sharealike. Additional terms may apply for the media files.