2019 Banja Luka Challenger – Doubles
Andrej Martin and Hans Podlipnik Castillo were the defending champions[1] but chose not to defend their title.
Doubles | |
---|---|
2019 Banja Luka Challenger | |
Champions | ![]() ![]() |
Runners-up | ![]() ![]() |
Final score | 6–3, 7–6(7–4) |
Sadio Doumbia and Fabien Reboul won the title after defeating Sergio Galdós and Facundo Mena 6–3, 7–6(7–4) in the final.
Seeds
Tomislav Draganja / Luca Margaroli (Quarterfinals) Ruben Gonzales / Andreas Siljeström (First round) Ivan Sabanov / Matej Sabanov (Semifinals) Sadio Doumbia / Fabien Reboul (Champions)
Draw
Key
- Q = Qualifier
- WC = Wild Card
- LL = Lucky Loser
- Alt = Alternate
- SE = Special Exempt
- PR = Protected Ranking
- ITF = ITF entry
- JE = Junior Exempt
- w/o = Walkover
- r = Retired
- d = Defaulted
First Round | Quarterfinals | Semifinals | Final | ||||||||||||||||||||||||
1 | ![]() ![]() | 6 | 6 | ||||||||||||||||||||||||
![]() ![]() | 4 | 3 | 1 | ![]() ![]() | 2 | 4 | |||||||||||||||||||||
WC | ![]() ![]() | 2 | 2 | ![]() ![]() | 6 | 6 | |||||||||||||||||||||
![]() ![]() | 6 | 6 | ![]() ![]() | 77 | 6 | ||||||||||||||||||||||
3 | ![]() ![]() | 77 | 7 | 3 | ![]() ![]() | 63 | 3 | ||||||||||||||||||||
![]() ![]() | 64 | 5 | 3 | ![]() ![]() | 6 | 7 | |||||||||||||||||||||
![]() ![]() | 2 | 2 | ![]() ![]() | 4 | 5 | ||||||||||||||||||||||
![]() ![]() | 6 | 6 | ![]() ![]() | 3 | 64 | ||||||||||||||||||||||
![]() ![]() | 3 | 4 | 4 | ![]() ![]() | 6 | 77 | |||||||||||||||||||||
![]() ![]() | 6 | 6 | ![]() ![]() | 3 | 5 | ||||||||||||||||||||||
WC | ![]() ![]() | 62 | 5 | 4 | ![]() ![]() | 6 | 7 | ||||||||||||||||||||
4 | ![]() ![]() | 77 | 7 | 4 | ![]() ![]() | 6 | 6 | ||||||||||||||||||||
![]() ![]() | 1 | 6 | [10] | WC | ![]() ![]() | 4 | 1 | ||||||||||||||||||||
![]() ![]() | 6 | 3 | [7] | ![]() ![]() | |||||||||||||||||||||||
WC | ![]() ![]() | 7 | 6 | WC | ![]() ![]() | w/o | |||||||||||||||||||||
2 | ![]() ![]() | 5 | 3 |
gollark: I am not accepting feedback on this at this time. Goodbye.
gollark: You're clearly wrong due to the Cayley-Hamilton theorem, various gollariosity axioms, and a trivial proof by contradiction by meanness.
gollark: None of those actually exist, see.
gollark: Clearly false.
gollark: That doesn't exist.
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