2015 Internationaux de Strasbourg – Singles

Monica Puig was the defending champion, but lost in the first round to Samantha Stosur.

Singles
2015 Internationaux de Strasbourg
Champion Samantha Stosur
Runner-up Kristina Mladenovic
Final score3–6, 6–2, 6–3
Seeds8
Main article: 2015 Internationaux de Strasbourg

Third-seeded Stosur went on to win the title, defeating Kristina Mladenovic in the final, 3–6, 6–2, 6–3.

Seeds
  1. Madison Keys (Quarterfinals, withdrew)
  2. Jelena Janković (Quarterfinals, retired)
  3. Samantha Stosur (Champion)
  4. Alizé Cornet (Second round)
  5. Zarina Diyas (First round)
  6. Coco Vandeweghe (Second round)
  7. Madison Brengle (First round)
  8. Mona Barthel (First round, retired)

Draw

Key

Finals
Semifinals Final
          
Kristina Mladenovic 6 1
WC Virginie Razzano 3 2r
Kristina Mladenovic 6 2 3
3/WC Samantha Stosur 3 6 6
3/WC Samantha Stosur 6 3 6
Sloane Stephens 3 6 0

Top half
First Round Second Round Quarterfinals Semifinals
1 M Keys 6 6
C McHale 4 3 1 M Keys 4 77 77
M Lučić-Baroni 1 M Lučić-Baroni 6 63 60
Q O Govortsova 2r 1 M Keys
K Mladenovic 6 4 6 K Mladenovic w/o
P Parmentier 2 6 1 K Mladenovic 77 6
A Riske 7 4 6 A Riske 64 2
5 Z Diyas 5 6 1 K Mladenovic 6 1
4 A Cornet 6 6 WC V Razzano 3 2r
Q Q Wang 3 3 4 A Cornet 6 0 3
E Vesnina 6 6 E Vesnina 3 6 6
Q G Dabrowski 4 2 E Vesnina 6 1 1
WC F Schiavone 6 6 WC V Razzano 4 6 6
L Davis 4 1 WC F Schiavone 2 3
WC V Razzano 6 5 WC V Razzano 6 6
8 M Barthel 2 5r

Bottom half
First Round Second Round Quarterfinals Semifinals
7 M Brengle 1 1
A Tomljanović 6 6 A Tomljanović 78 3 6
A Krunić 1 1 S Rogers 66 6 2
S Rogers 6 6 A Tomljanović 4 6 4
L Tsurenko 6 77 3/WC S Stosur 6 3 6
Q V Lepchenko 4 64 L Tsurenko
M Puig 0 3 3/WC S Stosur w/o
3/WC S Stosur 6 6 3/WC S Stosur 6 3 6
6 C Vandeweghe 77 7 S Stephens 3 6 0
LL O Dodin 63 5 6 C Vandeweghe 3 4
Q N Kichenok 3 0 S Stephens 6 6
S Stephens 6 6 S Stephens 6 0
S Zheng 6 0 6 2/WC J Janković 1 0r
Q S-w Hsieh 4 6 2 S Zheng 3 3
I Falconi 66 3 2/WC J Janković 6 6
2/WC J Janković 78 6

Qualifying

Seeds

The top two seeds and Océane Dodin received a bye into the qualifying competition.

  1. Varvara Lepchenko (Qualified)
  2. Wang Qiang (Qualified)
  3. Olga Govortsova (Qualified)
  4. Alla Kudryavtseva (Withdrew, still playing in Rome)
  5. Hsieh Su-wei (Qualified)
  6. Taylor Townsend (First round)
  7. Anna Tatishvili (First round)
  8. Océane Dodin (Qualifying competition, Lucky loser)
  9. Zhang Kailin (Qualifying competition)
  10. Risa Ozaki (Qualifying Competition)
  11. Hiroko Kuwata (First round)
  12. Gabriela Dabrowski (Qualified)
  13. Katarzyna Piter (Qualifying competition)

Qualifiers
  1. Varvara Lepchenko
  2. Wang Qiang
  3. Olga Govortsova
  4. Gabriela Dabrowski
  5. Hsieh Su-wei
  6. Nadiia Kichenok

Lucky Losers
  1. Océane Dodin

Draw

First qualifier
First Round Qualifying Competition
1 Varvara Lepchenko 6 6
  Constance Sibille 6 6   Constance Sibille 3 0
11 Hiroko Kuwata 1 2

Second qualifier
First Round Qualifying Competition
2 Wang Qiang 7 6
  Laura Schaeder 63 4 9 Zhang Kailin 5 3
9 Zhang Kailin 77 6

Third qualifier
First Round Qualifying Competition
          
3 Olga Govortsova 6 6
WC Margot Decker 1 1
3 Olga Govortsova 6 6
  Asia Muhammad 2 2
  Asia Muhammad 4 78 6
7 Anna Tatishvili 6 66 2

Fourth qualifier
First Round Qualifying Competition
          
13 Katarzyna Piter 6 6
  Françoise Abanda 3 3
13 Katarzyna Piter 6 2 3
12 Gabriela Dabrowski 1 6 6
  Irina Ramialison 4 2
12 Gabriela Dabrowski 6 6

Fifth qualifier
First Round Qualifying Competition
5 Hsieh Su-wei 6 6
WC Sarah Finck 0 3 5 Hsieh Su-wei 7 7
8 Océane Dodin 5 5

Sixth qualifier
First Round Qualifying Competition
          
6 Taylor Townsend 4 1
  Nadiia Kichenok 6 6
  Nadiia Kichenok 6 6
10 Risa Ozaki 3 4
WC Lou Brouleau 6 4 0
10 Risa Ozaki 2 6 6
gollark: If you wanted to ocnvert a number into a vector of digits, the right way would be repeated div/mod-ing.
gollark: Is that not the standard tool for reverse engineering?
gollark: However, why even.
gollark: - convert `n` to string- map over all chars, converting them to strings and then... parsing them as integers...? and crashing on error- collect the resulting ints together
gollark: It's simple*!

References
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