1998 Romanian Open – Doubles

The 1998 Romanian Open was a men's tennis tournament played on Clay in Bucharest, Romania that was part of the International Series of the 1998 ATP Tour. It was the sixth edition of the tournament and was held from 14 September – 21 September.

Doubles
1998 Romanian Open
Champions Andrei Pavel
Gabriel Trifu[1]
Runners-up George Cosac
Dinu Pescariu
Final score7–6, 7–6

Seeds

Champion seeds are indicated in bold text while text in italics indicates the round in which those seeds were eliminated.

  1. Julián Alonso / Javier Sánchez (First Round)
  2. Tom Kempers / Menno Oosting (Semifinals)
  3. Kent Kinnear / Aleksandar Kitinov (First Round)
  4. Nebojsa Djordjevic / Libor Pimek (Semifinals)

Draw

Key

Finals
First Round Quarterfinals Semifinals Final[1]
Á Calatrava
A Portas 		7 6
1 J Alonso
J Sánchez 		6 2 Á Calatrava
A Portas 		3 4
A Pavel
G Trifu 		6 6 A Pavel
G Trifu 		6 6
G Castrichella
F Maggi 		1 2 A Pavel
G Trifu 		6 6
4 N Djordjevic
L Pimek 		6 6 4 N Djordjevic
L Pimek 		2 3
M Calugaru
R Farcas 		4 4 4 N Djordjevic
L Pimek 		5 6 6
E Benfele Álvarez
M Puerta 		6 6 E Benfele Álvarez
M Puerta 		7 4 1
A Ilie
R Sabău 		2 4 A Pavel
G Trifu 		7 4 7
A Sávolt
T Shimada 		6 6 G Cosac
D Pescariu 		6 6 6
J Apell
B Karbacher 		3 0 A Sávolt
T Shimada 		3 5
G Cosac
D Pescariu 		6 6 G Cosac
D Pescariu 		6 7
3 K Kinnear
A Kitinov 		1 3 G Cosac
D Pescariu 		5 6 6
I Moldovan
A Voinea 		6 6 2 T Kempers
M Oosting 		7 2 3
L Bale
M Wakefield 		4 3 I Moldovan
A Voinea 		1 6 2
2 T Kempers
M Oosting 		6 7 2 T Kempers
M Oosting 		6 4 6
T Vanhoudt
F Wibier 		1 6
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References
  1. "1998 Bucharest". International Tennis Federation. Retrieved 4 January 2015.
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