1998 Dutch Open – Doubles

The 1998 Dutch Open was an ATP-tournament held in Amsterdam, Netherlands. The tournament was held from August 3 to August 9.

Doubles
1998 Dutch Open
Champions Jacco Eltingh
Paul Haarhuis[1]
Runners-up Dominik Hrbatý
Karol Kučera
Final score6–3, 6–2

Seeds

Champion seeds are indicated in bold text while text in italics indicates the round in which those seeds were eliminated.

  1. Jacco Eltingh / Paul Haarhuis (Champions)
  2. Neil Broad / Piet Norval (First Round)
  3. Tom Kempers / Daniel Orsanic (First Round)
  4. Jiří Novák / David Rikl (First Round)

Draw

Key

Finals
First Round Quarterfinals Semifinals Final[1]
1 J Eltingh
P Haarhuis 		4 6 6
C Haggard
J Waite 		6 3 3 1 J Eltingh
P Haarhuis 		6 3 6
J van Lottum
D van Scheppingen 		7 6 6 J van Lottum
D van Scheppingen 		3 6 3
L Pimek
T Anzari 		6 7 4 1 J Eltingh
P Haarhuis 		6 3 6
F Bergh
P Vízner 		6 6 6 F Bergh
P Vízner 		3 6 3
3 T Kempers
D Orsanic 		4 7 3 F Bergh
P Vízner 		6 3 6
M Hood
T Vanhoudt 		7 6 M Hood
T Vanhoudt 		1 6 2
S Noteboom
M Puerta 		6 1 1 J Eltingh
P Haarhuis 		6 6
C Doseděl
A Olhovskiy 		4 7 6 D Hrbatý
K Kučera 		3 2
M Barnard
B Barnard 		6 6 1 C Doseděl
A Olhovskiy 		w/o
G Köves
P Rosner 		6 4 7 G Köves
P Rosner
4 J Novák
D Rikl 		2 6 6 C Doseděl
A Olhovskiy 		6 3 4
N Djordjevic
J Holmes 		7 6 6 D Hrbatý
K Kučera 		2 6 6
P Albano
F Meligeni 		6 7 1 N Djordjevic
J Holmes 		5 7 2
D Hrbatý
K Kučera 		5 6 6 D Hrbatý
K Kučera 		7 6 6
2 N Broad
P Norval 		7 4 3
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References
  1. "1998 Amsterdam". International Tennis Federation. Retrieved 1 January 2015.
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