1890 Kansas gubernatorial election

The 1890 Kansas gubernatorial election was held on November 4, 1890. Incumbent Republican Lyman U. Humphrey defeated People's Party nominee John F. Willits with 39.05% of the vote.

1890 Kansas gubernatorial election
November 4, 1890
 
Nominee Lyman U. Humphrey John F. Willits Charles L. Robinson
Party Republican People's Democratic
Popular vote 115,024 106,945 71,357
Percentage 39.05% 36.31% 24.23%
Governor before election

Lyman U. Humphrey
Republican

 Elected Governor

Lyman U. Humphrey
Republican

Elections in Kansas

General election

Candidates

Major party candidates

  • Lyman U. Humphrey, Republican
  • Charles L. Robinson, Democratic

Other candidates

  • John F. Willits, People's
  • A. M. Richardson, Prohibition

Results
1890 Kansas gubernatorial election[1]
Party Candidate Votes % ±
Republican Lyman U. Humphrey 115,024 39.05%
People's John F. Willits 106,945 36.31%
Democratic Charles L. Robinson 71,357 24.23%
Prohibition A. M. Richardson 1,230 0.42%
Majority 8,079
Turnout
Republican hold Swing
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References
  1. "Guide to U.S. elections - CQ Press, Congressional Quarterly, inc". Books.google.com. Retrieved 2020-07-05.
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